The most one-sided title match ever

World Championship 1910: Lasker – Janowski

8 November – 8 December 1910 · Berlin, Germany
Lasker won 9½–1½

Ten months after Schlechter nearly dethroned him, Lasker defended again — this time against David Janowski, and won without losing a game. Lasker's eight wins to none remains the most lopsided result in the history of the World Championship.

Dates
8 November – 8 December 1910
Venue
Berlin, Germany
Format
First to 8 wins
Result
Lasker 9½ – 1½ Janowski

Janowski's backer

The brilliant, erratic Dawid Janowski was a fearsome attacker but a notoriously poor defender — and his championship bid was underwritten by the wealthy art patron Pierre Nardus, who admired him. The two players had already met in exhibition matches in 1909; the longer of those is sometimes miscalled a title match, though the crown was not actually at stake.

This time it was, under the now-standard first-to-eight-wins rule.

A record that still stands

Janowski never came close. Lasker won eight games, drew three, and lost none — a final score of 9½–1½ that stands as the most one-sided World Championship match ever played.

It would be Lasker's last title defence for over a decade. When he finally sat down again for the crown, in Havana in 1921, it was to lose it to José Raúl Capablanca.

9½–1½
Final score
0
Games Janowski won
8–0
Wins to losses
#1
Most one-sided WC match

Cross Table

9½–1½
Lasker won · official result +8-0=3
Player 1 2 3 4 5 6 7 8 9 10 11 Pts
Lasker 1½½11½11111
Janowski 0½½00½00000

1 win · ½ draw · 0 loss — click a game number to replay it.